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1956 Wimbledon Championships – Women's Singles : ウィキペディア英語版 | 1956 Wimbledon Championships – Women's Singles
Shirley Fry (USA) defeated Angela Buxton (GBR) 6–3, 6–1 in the final to win the Ladies' Singles tennis title at the 1956 Wimbledon Championships. ==Seeds== The seeded players are listed below. Shirley Fry is the champion; others show the round in which they were eliminated. # Louise Brough ''(Semifinalist)'' # Beverley Fleitz ''(Quarterfinalist)'' # Angela Mortimer ''(Quarterfinalist)'' # Althea Gibson ''(Quarterfinalist)'' # Shirley Fry ''(Champion)'' # Angela Buxton ''(Finalist)'' # Dorothy Knode ''(Second round)'' # Shirley Bloomer ''(Quarterfinalist)''
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